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Get the file path for Source Extract for given extract and year

Usage

get_source_extract_path(
  year,
  type = c("acute", "ae", "at", "ch", "client", "cmh", "dd", "deaths", "dn", "gp_ooh",
    "hc", "homelessness", "maternity", "mh", "outpatients", "pis", "sds"),
  ...
)

Arguments

year

Year of extract

type

Name of clean source extract

...

additional arguments passed to get_file_path()

Value

Path to clean source extract containing data for each dataset